MTH302 Assignment 2 Solution
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Assignment No. 2
Solution MTH302 Spring 2021
Question 1
Classify the data into groups by making 7 number of classes. Also calculate the frequency, relative frequency and class mark for each class.
100, 89, 70, 44, 60, 75, 80, 77, 44, 40, 57, 65, 58, 90, 85, 61, 49, 76, 93, 52, 87, 43, 51, 73, 82, 69, 71, 41, 91, 47
Solution
Sort form :40,41,43,44,44,47,49,51,52,57,58,60,61,65,69,70,71,73,75,76,77,80,82,85,87,89,90,91,93,100
Now Using the Class Interval Formula.
· Class Interval= Xm-Xo/Number Of Class
Class Interval=100-40/7
Class Interval =60/7
Class Interval =8.6
Class Interval ~9
Now We Have Drawn A Table.
NO. | Classes | Tally Marks | Frequency | Relative Frequency | Class Mark |
1 | 38-46 |
| 5 | 5/30=0.167 | 42 |
2 | 47-55 | \\\\ | 4 | 4/30=0.133 | 51 |
3 | 56-64 | \\\\ | 4 | 4/30=0.133 | 60 |
4 | 65-73 |
| 5 | 5/30=0.167 | 69 |
5 | 74-82 |
| 5 | 5/30=0.167 | 78 |
6 | 83-91 |
| 5 | 5/30=0.167 | 87 |
7 | 92-100 | \\ | 2 | 2/30=0.067 | 96 |
| | | Σf=30 | | |
| | | | | |
Question 2 Marks=10
Calculate Mean deviation about mean and co-efficient of mean deviation for the following salaries:
Rs. 1030, Rs.500, Rs.680, Rs.1100, Rs.1080, Rs.1740. Rs.1050, Rs.1000, Rs.2000, Rs.2250, Rs. 3500 and Rs.1030.
Solution;
Sort form: 500,680,1000,1030,1030,1050,1080,1740,1100,2000,2550,3500
Mean = x̄ = Σx/n
Mean=x̄=500+680+1000+1030+1030+1080+1100++1740+2000+2250+2250/12
Mean= x̄=16690/12
Mean= x̄=1413.33
Now we have drawn a Table
X(Rs.) | x- x̄ | |x – x̄| |
500 | -913.33 | 913.33 |
680 | -733.33 | 733.33 |
1000 | -413.33 | 413.33 |
1030 | -383.33 | 383.33 |
1030 | -383.33 | 383.33 |
1050 | -363.33 | 363.33 |
1080 | -333.33 | 333.33 |
1100 | -313.33 | 313.33 |
1740 | 326.67 | 326.67 |
2000 | 586.67 | 586.67 |
2250 | 836.67 | 836.67 |
3500 | 2086.67 | 2086.67 |
| | Σ|x – x̄|=7673.32 |
Mean Deviation for Mean= Σ|x – x̄|/n
Mean Deviation for Mean=7673.32/12
=639.44
Co-efficient of mean Deviation= Mean Deviation from Mean / Mean
Co-efficient of mean Deviation=639.44 /1413.33
Co-efficient of mean Deviation=0.4524
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1 Comments
hey dear very good artical
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